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Hangover(1.4.1)
阅读量:6213 次
发布时间:2019-06-21

本文共 1643 字,大约阅读时间需要 5 分钟。

Description

How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're assuming that the cards must be perpendicular to the table.) With two cards you can make the top card overhang the bottom one by half a card length, and the bottom one overhang the table by a third of a card length, for a total maximum overhang of 1/2 + 1/3 = 5/6 card lengths. In general you can make n cards overhang by 1/2 + 1/3 + 1/4 + ... + 1/(n + 1) card lengths, where the top card overhangs the second by 1/2, the second overhangs tha third by 1/3, the third overhangs the fourth by 1/4, etc., and the bottom card overhangs the table by 1/(n + 1). This is illustrated in the figure below.

Input

The input consists of one or more test cases, followed by a line containing the number 0.00 that signals the end of the input. Each test case is a single line containing a positive floating-point number c whose value is at least 0.01 and at most 5.20; c will contain exactly three digits.

Output

For each test case, output the minimum number of cards necessary to achieve an overhang of at least c card lengths. Use the exact output format shown in the examples.

Sample Input

1.003.710.045.190.00

Sample Output

3 card(s)61 card(s)1 card(s)273 card(s)
#include 
#include
using namespace std;int main(){
double n;int i;while(cin>>n&&n!=0.00){
double a=0.00;for(i=2;i<10000;i++){
a=a+double(1.0/i);if(a>=n)break;}cout<
<<" card(s)"<
注意要用0.1对double类型进行乘除

转载于:https://www.cnblogs.com/lengxia/p/4387854.html

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